Circuit diagram
A component list
2x1n4007 Diode
2x capasitor 33mF
1xZener diode
1x voltage regulator LM317
1xR1
1xR2
1xR3
1xLED
1x PC Boards Vero Type Strip
1x PC Boards Vero Type Strip
Calculations
Calculate the values of R3,R2
Vref=1.25
Vout=5v
Use Vout=Vref (1+R3/R2)
5 = 1.25(1+R3/R2)
5/1.25 = 1+R3/R2
4 = 1+R3/R2
4 - 1 = R3/R2
3 = R3/R2
R3 = 3 x R2
This mean that R3 is 3 times bigger than R2, So we were given 330R for R2 and 1K resistor for R3.
For R1: LED resistor
R1 = (VS - VL) / I
R1 = (5-2.1)/30
R1 = 100 R
Lockmaster
A Technical Explanation
This is a normal voltage regulation circuit. As the raw 12V is presented into the circuit, it goes through the diode (These diodes 1N4001 is to prevent back EMF) using 0.7V so 11.3V goes into the regulator (The regulator is a LM317T) which is then stepped down to 5V. C1 and C2 are 33 mF , the capacitors job is to provide stability in the output voltage .The 2 zener is a 2V2 zener. . The R1 100R with the LED is a indicator to tell if there is voltage going through the circuit. R2 is 330 R and R3 is 1 K, R2 and R3 are used to determine how much voltage output will be.
This is a normal voltage regulation circuit. As the raw 12V is presented into the circuit, it goes through the diode (These diodes 1N4001 is to prevent back EMF) using 0.7V so 11.3V goes into the regulator (The regulator is a LM317T) which is then stepped down to 5V. C1 and C2 are 33 mF , the capacitors job is to provide stability in the output voltage .The 2 zener is a 2V2 zener. . The R1 100R with the LED is a indicator to tell if there is voltage going through the circuit. R2 is 330 R and R3 is 1 K, R2 and R3 are used to determine how much voltage output will be.
Test Procedure
12V to the input and out put should be 12v on the red wire and 5v on the yellow wire and black to ground (negative)
12V to the input and out put should be 12v on the red wire and 5v on the yellow wire and black to ground (negative)
Reflection
I wouldn't do anything different if i was to build the circuit again. as my circuit worked first time, so i dont see how i could make a different.
I wouldn't do anything different if i was to build the circuit again. as my circuit worked first time, so i dont see how i could make a different.
Finish result
